Question

Find the interval of convergence of the power series:  ∑k=1∞2k2(x+2) k\sum _ { k = 1 } ^ { \infty } \frac { 2 } { k ^ { 2 } } ( x + 2 )  ^ { k }∑k=1∞​k22​(x+2) k

Accepted Answer

A)   (-3, -1) 
B)   [-3, -1) 
C)   [-3, -1]
D)   (-3, -1] E) A) and D)
F) A) and C)

Exam 8: Power Series

Find the interval of convergence of the power series: $\sum _ { k = 1 } ^ { \infty } \frac { 2 } { k ^ { 2 } } ( x + 2 ) ^ { k }$

Correct Answer
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Exam 8: Power Series

Find the interval of convergence of the power series: ∑k=1∞2k2(x+2) k\sum _ { k = 1 } ^ { \infty } \frac { 2 } { k ^ { 2 } } ( x + 2 ) ^ { k }∑k=1∞​k22​(x+2) k

Correct AnswerverifiedShow Answer

Find the interval of convergence of the power series: $\sum _ { k = 1 } ^ { \infty } \frac { 2 } { k ^ { 2 } } ( x + 2 ) ^ { k }$

Correct Answer
verified